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1 mol N(2)H(4) loses 10 mol of electrons...

1 mol `N_(2)H_(4)` loses 10 mol of electrons with th electrons with the formation of I mol of a new compound y. of the new compound contains same number of N- atoms then what will be the oxidation number of nitrogen in the new compound ? (Assume that the oxidation number of H -atom does not change)

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Oxidation number of each N- atoms in `N_(2)H_(4)=2`
As given ,1 mol `N_(2)H_(4)to1`mol Y+10mol e
Suppose ,oxdation of N in a molecule of Y=x,
`therefore` Total oxidation number of two N-atoms in Y- molecule =Oxidation number of two N - atoms in `N_(2) H_(4)` molecule +10 or, 2x =2(-2)+10 or, x =+3
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