Consider the following reaction `XMNO_(4)^(-)+yC2O_(4)^(2-)+zH^(+)toxMn^(2+)+2yCO_(2)+(z)/(2)H_(2)O`
The values of x,y and x in the reaction are, respectively -

Options

A. 5,2 and 8
B. 5,2 and 16
C. 2,5 and 8
D. 2,5 and 16

Answer

D

Explanation

`[MnO_(4)^(-)+8H^(+)+5etoMn^(2+)+4H_(2)O]xx2`
`underline([C_(2)O_(4)^(2-)to2CO_(2)+2e]xx5)`
` 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+)to2M^(2+)+10CO_(2)+8H_(2)O`
`therefore`x=2 ,y=5 and z= 16