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In acidic medium H(2)O(2) changes Cr(2)(...

In acidic medium `H_(2)O_(2)` changes `Cr_(2)_(7)^(2-)`to`CrO_(5)`which has two (-O-O) bonds oxidation state of Cr in `CrO_(5)`is -

A

`+5`

B

`+3`

C

`+6`

D

`-10`

Text Solution

Verified by Experts

The correct Answer is:
C
Let the oxidation number of Cr in `CrO_(5)` be x
therefore `thereforeunderset(("forOatoms in -o-bonds"))(x+4xx(-1))+underset(("for the remainig Oatoms"))(1xx(-2)=0)therefore=+6`
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