For the redox reaction -
`MnO_(4)^(-)+C_(2)O_(4)^(2-)+H^(+)toMn^(2+)+CO_(2)+H_(2)O`
The correct coefficients of the reactants for the balanced equation are

Options

A. `{:(MnO_(4)^(-) , C_(2) O_(4)^(2-) , H^(+)), (16 , 5 , 2):}`
B. `{:(MnO_(4)^(-) , C_(2) O_(4)^(2-) , H^(+)), (2 , 5 , 16):}`
C. `{:(MnO_(4)^(-) , C_(2) O_(4)^(2-) , H^(+)), (2 , 16 , 5):}`
D. `{:(MnO_(4)^(-) , C_(2) O_(4)^(2-) , H^(+)), (5 , 16 , 2):}`

Answer

B

Explanation

`[MnO_(4)^(-)+8H^(+)+5etoMn^(2+)+4H_(2)O]xx2`
`underline([C_(2)O_(4)^(2-)to2CO_(2)+2e]xx5)`
` 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+)to2M^(2+)+10CO_(2)+8H_(2)O`