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If underset(k = 1)overset(n)sumtan^(-1)...

If `underset(k = 1)overset(n)sumtan^(-1)((1)/(k^(2)+k+1))= tan^(-1)(theta) , " then " theta = `

A

`(n)/(n +2)`

B

`(n)/(n +1)`

C

1

D

`(n)/(n - 1)`

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The correct Answer is:
A
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