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If ABCD is a cyclic quadrilateral with A...

If ABCD is a cyclic quadrilateral with AB = 6 , BC = 4, CD = 5, DA= 3 and `angleABC = theta `, then cos `theta` =

A

A `(3)/(13)`

B

B `(18)/(76)`

C

C `(16)/(78)`

D

D `(78)/(86)`

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A
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