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If f: [0,3] to [0,3] is defined by: f...

If `f: [0,3] to [0,3]` is defined by:
`f(x) = {{:(1+x,0 le x le 2),(3-x, 2 lt x le 3):}` , then show that `f[0,3] sube [0,3]` and find fof.

A

Conrinuous at x = 1

B

Continuous at x =2

C

Discontinuous at x =1 and x=2

D

Continuous on [0,3]

Text Solution

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The correct Answer is:
C
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