A gun and a target are at the same horizontal level separated by a distance of 600 m. The bullet is fired from the gun with the velocity of `500 ms^-1` In order to hit the target , the gun should be aimed to a height h above the target. The value of h is (Acceleration due to gravity,`g=10 ms^-2`)

Options

A. 2.4 m
B. 3.6 m
C. 7.2 m
D. 10.8 m

Explanation

Given
distance between gun and target =600 m
velocity of bullet=`500ms^-1`
Now, distance = velocity of bullet `times` time
`600=500 times t`
`t=600/500=6/5=1.2 sec`
From second equation of the motion,
`h=ut+1/2 gt^2`
Putting the gives values ,we get
`h=0times(1.2) +1/2 times(-10) times(0.2)^2`
`h=1/2times(-10) (1.2 times1.2)`
`h=-7.2 m`
`|h|=7.2 m`