At a certain place the horizontal component of earth's magnetic field is `(1)/(sqrt3)` times the vertical component. The angle of dip at that place is

Options

A. `30^(@)`
B. `45^(@)`
C. `60^(@)`
D. `90^(@)`

Answer

C

Explanation

Given, `B_(H)//B_(V)= 1//sqrt3`
where, `B_(H) and B_(V)` are respectively, the horizontal and vertical components of earth.s magnetic field
`tan delta =B_(V)//B_(H) = (sqrt3 B_(H))/(B_(H)) = sqrt3`
`delta = tan^(-1) sqrt3 = 60^(@)`
Angle of dip, `delta = 60^(@)`