The copper (II) halide which does not exist is

Options

A. `CuF(2)`
B. `CuBr_(2)`
C. `"Cu"l_(2)`
D. `CuCl_(2)`

Answer

C

Explanation

`CuI_(2)` is not stable and thus does not exist iodide ion will act as reducing agent that converts Cu(II) to Cu(I) and part of iodide ion will be oxidised to iodine. The first reaction involved is as follows :
`2Cu^(2+)(aq) +4I^(-)(aq) to 2CuI(s) +I_(2) (aq)`