`2Cu_(2)O(s)+Cu_(2)(s) rarr 6Cu(s) +SO_(2)(g)` the oxidant and reductant respectively in the above reaction are

Options

A. oxide of `Cu_(2)O` and sulphide of `Cu_(2)S`
B. suphide of `Cu_(3)S` and oxide of `Cu_(2)O`
C. `Cu (I) of Cu_(2)O , Cu_(2)S` and sulphide of `Cu_(2)S`
D. Cu (I) of `Cu_(2)S, Cu (I) ` of `Cu_(2)O`

Answer

C

Explanation

Cu(I) of `Cu_(2)O(s) ` and `Cu_(2)S(s)` undergoes reduction to form Cu(s) while sulphide of `Cu_(2)S` undergoes oxidation to form `SO_(2)(g).` Thus Cu(I) of `Cu_(2)O.Cu_(2)S ` acts as an oxidising agent (oxidant ) and sulphide of `Cu_(2)` S acts as a reducing agent (reductant ).