A glass prism is immersed in water. What change will take place in the value of the angle of minimum deviation?

Explanation

If the refractive indices of the material of the prism in air and water be `a^(mu)b and w^(mu)g` respectively.
Then we can write, ` a^(mu)g = (sin(A + delta_(m))/(sin""(A)/(2))) and w^(mu)g = (sin(A + delta._(m))/(sin""(A)/(2)))`
`"Since, " " " w^(mu)g lt a^(mu)g`
`"Therefore, " " delta._(m) lt delta_(m)`
i.e, the angle of minimum deviation decreases due to immersion of the prism in water.