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The angle of incidence for a ray of ligh...

The angle of incidence for a ray of light at a refracting surface of a prism is `45^(@)` . The angle of prism is `60^(@)` . If the ray surface minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are:

A

`30^(@)` ,` sqrt(2)`

B

`45^(@)` , `sqrt(2)`

C

`30^(@)` , `(1)/(sqrt(2))`

D

`45^(@)` , `(1)/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
Minimum angle of deviation,
`delta_(m) = 2i - A = 2 xx 45^(@) - 60^(@) = 30^(@)`
`"For minimum deviaton", r_(1) = (A)/(2) = (60^(@))/(2) = 30^(@)`
For refraction at point P
`sin45^(@) = musin30^(@) or, mu = sqrt(2)`
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Knowledge Check

  • The angle of deviation of a ray of light refracted through a parallel glass slab is

    A
    `45^(@)`
    B
    `0^(@)`
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  • The refractive index of a prism is sqrt(2) and its refractive angle is 60^(@) . If a ray emerge with the minimum angle of deviation then the angle of incidence will be

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    D
    `150^(@)`

  • The angle of deviation will be greater in case of a prism for light of

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    B
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    C
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    D
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