The angle of incidence for a ray of light at a refracting surface of a prism is `45^(@)` . The angle of prism is `60^(@)` . If the ray surface minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are:
A
`30^(@)` ,` sqrt(2)`
B
`45^(@)` , `sqrt(2)`
C
`30^(@)` , `(1)/(sqrt(2))`
D
`45^(@)` , `(1)/(sqrt(2))`
Text Solution
Verified by Experts
The correct Answer is:
A
Minimum angle of deviation, `delta_(m) = 2i - A = 2 xx 45^(@) - 60^(@) = 30^(@)` `"For minimum deviaton", r_(1) = (A)/(2) = (60^(@))/(2) = 30^(@)` For refraction at point P `sin45^(@) = musin30^(@) or, mu = sqrt(2)`
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