Home
Class 11
PHYSICS
The period of osciIIation of a simpIe pe...

The period of osciIIation of a simpIe penduIum is T = `2 pi sqrt((l)/(g))`. Length `l` is adout 10 cm and is Known to 1 mm accuracy. The period of osciIIation is about 0.5 s. The time of 100 osciIIations is measured with a wristwatch that shows the minimum intervaI of time as Is (i.e. Ieast count = 1s ). What is the percentage of accuracy in the determination of g?

Text Solution

Verified by Experts

The correct Answer is:
5
Promotional Banner

Topper's Solved these Questions

  • MEASUREMENT AND DIMENSION OF PHYSICAL QUANTITY

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE with solutions (WBCHSE )|15 Videos
  • MEASUREMENT AND DIMENSION OF PHYSICAL QUANTITY

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE with solutions (WBJEE )|4 Videos
  • MEASUREMENT AND DIMENSION OF PHYSICAL QUANTITY

    CHHAYA PUBLICATION|Exercise Comprehension type|8 Videos
  • KINETIC THEORY OF GASES

    CHHAYA PUBLICATION|Exercise CBSE Scanner|9 Videos
  • NATURE OF VIBRATION

    CHHAYA PUBLICATION|Exercise EXERCISE (CBSE SCANNER)|2 Videos

Similar Questions

Explore conceptually related problems

What is accuracy?

The period of oscillation of a simple pendulum is T = 2pisqrt((L)/(g)). Measured value of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1 s resolution. The accuracy in the determination of g is

If one measures the length of an obejct to be 2.70 mm with an instrument of least count 0.01 mm. what is the percentage error in the measurement?

Time period T of a simple pendulum of length l is given by T=2pisqrt((l)/(g)) . If the length is increased by 2% then an approximate change in the time period is