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A force of 30 dyn is inclined to the y-a...

A force of 30 dyn is inclined to the y-axis at an angle of `60^(@)` . Find the components of the force along x and y axes respectively.

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Given , F=30 dyn and `theta =60^(@)`
Hence, component of F along y-axis,
`F_(y)=F cos theta=Fcos 60^(@)=30xx1/2=15 dyn`
and component of F along x-axis
`F_(x)=F sin 60^(@)=30xxsqrt(3)/(2)=15sqrt(3) dyn`.
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