The value of the resultant of two mutually perpendicular forces is 80 dyn. The resultant makes an angle `60^(@)` with one of the forces. Find the magnitudes of the forces.

Explanation

Let the forces be `vec(P),vec(Q)` and the resulltant that makes an angle `60^@` with `vec(P) be vec(R)`.
Here,R=80 dyn
`therefore P=R cos theta =80 cos 60^@=80xx1/2=40 dyn`
`and Q=R sin 60^(@)=80 sin 60^(@)=80xxsqrt(3)/(2)=40sqrt(3) dyn`.