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The position vector of a particle is, ve...

The position vector of a particle is, `vecr=3thati-2t^2hatj+4hatk`. Find out
(ii) the magnitude and direction of its velocity at t=2s.

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`vecr=3thati-2t^2hatj+4hatk`
At t=2 s `vecv=3hati-(4xx2)hatj=3hati-8hatj`
(between x-axis and negative y-axis )
`|vecv|=sqrt(3^2+(-8)^2)=sqrt(73)` unit
Inclination of `vecv` with the x-axis,
`theta=tan^(-1)((-8)/(3))=-69.4^@`
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