A simple pendulum is suspended from the roof of a car moving horizontally with an acceleration of `10m*s^(-2)` . What will be the angle made by the pendulum in its equilibrium position with the vertical ? [g=`10 m*s^(-2)`]

Explanation

The acceleration of the car, `a=10m*s^(-2)` and acceleration due to gravity g`=10m*s^(-2)` . The pendulum will be inclined along the direction of apparent pull of the earth.
Let the angle made by the pendulum with the vertical be `theta` .
`therefore tan theta =a/g=(10)/(10)=1 or, theta =45^@`.