Find the angle between the vectors `vecA=2hati+3hatj and vecB=-3hati+2hatj`.

Explanation

Let the anlge between the two vector `vecA and vecB` be `theta`.
Now. `vecA*vecB= (2hati+3hatj)*(-3hati+2hatj)=-6+6=0`
As this dot product is zero, `vecA and vecB` are perpendicular to each other. So, the angle between them = `90^@`.