Find the projection of the vector `vecP=2hati-3hatj+6hatk` on the vector `vecQ=hati+2hatj+2hatk`.

Explanation

The projection of `vecP " "on" " vecQ` is
`P cos theta =(vecP*vecQ)/(|vecQ|)=(P_xQ_x+P_yQ_y+P_zQ_z)/(sqrt(Q_x^2+Q_y^2+Q_z^2))`
[where `theta` is the angle between `vecP and vecQ]`
`=((2*1)+[(-3)*2]+(6.2))/(sqrt(1^2+2^2+2^2))=(2-6+12)/(sqrt(9))=8/3`