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vecA=2hati+3hatj+4hatk and vecB=hati-hat...

`vecA=2hati+3hatj+4hatk and vecB=hati-hatj+hatk` are two vectors. Find `vecAxxvecB`.

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Verified by Experts

`vecAxxvecB=hati(A_yB_z-A_zB_y)+hatj(A_zB_x-A_xB_z)+hatk(A_xB_y-A_yB_x)`
`=hati{3*1-4*(-1)}+hatj(4*1-2*1)+hatk{2*(-1)-3*1} =7hati+2hatj-5hatk.`
Alternative method:
`vecAxxvecB=|{:(hati,hatj,hatk),(2,3,4),(1,-1,1):}|=hati(3+4)-hatj(2-4)+hatk(-2-3)=7hati+2hatj-5hatk`
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