Home
Class 11
PHYSICS
Statement I: The initial velocity of pro...

Statement I: The initial velocity of projectile `=(ahati+bhatj)` . The horizontal range becomes maximum for a=b.
Statement II: for the same magnitude of initial velocity , the horizontal range of a projectile becomes maximum for the angle `45^@` of projection.

A

Statement I is true , statement II is true, statement II is a correct explanation for statement I.

B

Statement I is true , statement II is true, statement II is not a correct explanation for statement I.

C

Statement I is true, statement II is false.

D

Statement I is false, statement II is true.

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • VECTOR

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER (Multiple correct answers type)|11 Videos
  • VECTOR

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER (Comprehension type)|10 Videos
  • VECTOR

    CHHAYA PUBLICATION|Exercise PROBLEM SET-II (Hot Numerical Problems)|24 Videos
  • THERMOMETRY

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIEVE - WBJEE|1 Videos
  • VISCOSITY AND SURFACE TENSION

    CHHAYA PUBLICATION|Exercise EXERCISE (CBSE SCANNER)|9 Videos

Similar Questions

Explore conceptually related problems

If the horizontal range is 4 times of the maximum height then what is the angle of projection?

Statement I: The horizontal range of a projectile is the same for angles 30 ^@ and 60^@ of projection. Statement II: The horizontal range of projectile is independent of the angle of projection.

Find the angle of projection of a projectile for which the horizontal range and the maximum height are equal.

Statement I: During the flight of a projectile, the horizontal component of its velocity remains uniform . Statement II: The vertical component of the velocity of a projectile becomes zero at the highest point of its path.

For a projectile, ("horizontal range")^2 =48xx("maximum height")^2 The angle of projection is

If the range of a projectile, projected from the surface of the earth is four times the maximum height attained, what is the angle of projection ?

The resultant velocity of a projectile at its highest point is sqrt(6/7) times that at half the maximum height. Show that the angle of projection with respect to the horizontal is 30^@ .

Two projectiles, thrown from the same point with the same magnitude of velocity . Have angles 60^@ and 30^@ of their projection. Then their

The initial velocity of a projectile is (hati+2hatj)m//s , where hati and hatj are unit vectors along the horizontal and vertical directions respectively. Find out the locus of the projectile , taking g=10 m//s^2 .