A mass m acquires a velocity v after covering a distance x, when a force F is applied on it for time t. show that, t `= (mv)/(F) and x = (1)/(2) (mv^(2))/(F)`.

If F = force is applied on a body of mass m for time t then it acquires the velocity V and displacement x. Then show that---- t=(mv)/F & x=1/2(mv^2)/F

A force F acts on a stationary body of mass m for a time t. Show that, the kinetic energy of the body iin that time =(F^2t^2)/(2m) .

Assuming velocity (V) time (T) and force (F) as the fundamental quantities find the dimension of density.

The initial velocity of a particle- is u and acceleration (f) is uniform. Final velocity and distance covered in the interval t are v and s respectively. Show that the velocity of the particle at half - distance is more than the velocity for half-time.

A body of mass m , starting from rest , moves with constant acceleration . After a time T it attains a velocity V. Show that the work done by the body in time t=1/2 m (V^2)/(T^2)*t^2*

The velocity v of a particle (under a force F) depends on its distance (x) from the origin (with x gt 0) v prop = (1)/(sqrt(x)) .Find how the magnitude of the force (F) on the particle depends on x.

If force (F), Work (W) and Velocity (V) are taken as fundamental quantities, then the dimensional formula of time (T) is