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A mass of 1 kg is suspended by a thread....

A mass of 1 kg is suspended by a thread. It is lifted up with an acceleration `4.9m/s^(2)`
(ii) lowered with an acceleration of 4.9 m`cdot s^(-2)`. The ratio of the tension on the thread is

A

`3:1`

B

`1:2`

C

`1:3`

D

`2:1`

Text Solution

Verified by Experts

Tension while lowering the mass,
`T_(2) = g - a = g - (g)/(2) = (g)/(2)`
`therefore" "T_(1) : T_(2) = (3g)/(2) : (g)/(2) = 3 : 1 `
The option A is correct.
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