Determine the angular velocities of the second, minute and hour hands of a clock.

Explanation

Since the second hand of a clock completes a circular revolution in 60 seconds, the angular velocity of the second hand is,
`omega = (2pi)/(60) = (pi)/(30) = 0.105 "rad" cdot s^(-1)`
Since the minute hand of a clock completes a circular revolution in 60 minutes, the angular velocity of the minute hand is,
`omega = (2pi)/(60 xx 60) = (pi)/(1800) = 1.75 xx 10^(-3) "rad" cdot s^(-1)` .
Since the hour of a clock completes a circular revolution in 12 hours, the angular velocity of the hour hand is,
`omega = (2pi)/(12 xx 60 xx 60) = (pi)/(21600) = 1.45 xx 10^(-4) "rad"cdot s^(-1)`.