A car of mass M moves up an inclined roa...

A car of mass M moves up an inclined road making an angle `theta` with the horizontal with constant speed v. if `mu` is the coefficient of friction between the type of the car and the road, show that the power of the engine of the car is `P=vMg(sin theta+mu cos theta)`.

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The upward acceleration along the inclined plane,
`a=g(sin theta+mu cos theta)`
Now the upward force acting on the car, F=Ma Hence, power of the car engine,
`P=Fv=vMg(sin theta +mu cos theta)`

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