A particle of mass m is rotated in a circular path of radius r under the influence of a force `F=-k/(r^2)`, where k is a constant. Find the total energy of the particle.

Explanation

`(mv^2)/r =k/(r^2)`
Kinetic energy
`=1/2 mv^2 =1/2*(kr)/(r^2)=k/(2r)`
Potential energy
`=-int_(oo)^r F*dr =k int _(oo)^r (dr)/(r^2)=-k/r`
`therefore` Total energy `=k/(2r)-k/r=-k/(2r)`