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A Time dependent force F=6t acts on a pa...

A Time dependent force F=6t acts on a particle of mass 1kg. If the particle starts from rest, the work done by the force during the first 1 s will be

A

4.5 J

B

22J

C

9J

D

18J

Text Solution

Verified by Experts

The correct Answer is:
A
Given ,F=6t
`or, m*(dv)/(dt)=6t or, int _0^v dv =6int_0^1tdt [m=1kg]`
`or, v=6[(t^2)/(2)]_0^1=3m*s^(-1)`
`therefore "Work done" ,W=DeltaKE=1/2mv^2=1/2xx1xx3^2=4.5J`
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