Home
Class 11
PHYSICS
The position vectors of two masses of 6 ...

The position vectors of two masses of 6 and 2 units are 6i-7j and 2i+5j-8k respectively. Deduce the position of their centre of mass.

Text Solution

Verified by Experts

Here `m_(1)` = 6 units, its position vector `vecr_(1)= 6hati-7hatj" "m_(2)`=2 units, its position vector `vecr_(2)= 2hati+5hatj-8hatk`
The position vector of the centre of mass of the two masses,
`vecr_("cm")=(m_(1)vecr_(1)+m_(2)vecr_(2))/(m_(1)+m_(2))`
`=(6(6hati-7hatj)+2(2hati+5hatj-8hatk))/(6+2)=5hati-4hatj-2hatk`
So, the coordinates of the centre of mass are (5,-4,-2).
Promotional Banner

Topper's Solved these Questions

  • STATICS

    CHHAYA PUBLICATION|Exercise HIGHER ORDER THINKING SKILL (HOTS) QUESTIONS|18 Videos
  • STATICS

    CHHAYA PUBLICATION|Exercise EXERCISE (Multiple Choice Questions )|14 Videos
  • SIMPLE HARMONIC MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|16 Videos
  • SUPERPOSITION OF WAVES

    CHHAYA PUBLICATION|Exercise CBSE Scanner|14 Videos

Similar Questions

Explore conceptually related problems

The position vector of two masses of 6 unit and 2 unit is (6hati-7hatj) & (2hati + 5hatj) respectively. Find out the position of their centre of mass.

Position vectors of two equal masses with respect to the origin are veca and vecb respectively. Position vector of the centre of mass of these masses is

If vec(a)=4vec(i)-3hat(j) " and " vec(b)=-2hat(i)+5hat(j) are the position vectors of the points A and B respectively, find (i) the position vector of the middle point of the line-segment bar(AB) , (ii) the position vectors of the points of trisection of the line-segment bar(AB) .

In a system comprising of two particles of mass 2 kg and 5 kg, the positions of the two particles at t=0 are (4hati+3hatj) and (6hati-7hatj+7hatk) respectively and the velocities are (10hati-6hatk) and (3hati+6hatj) respectively. Deduce the velocity of the centre of mass and the position of the centre or mass at t=0 and t=4 s

Two particles of masses 3 kg and 2kg are located at (-6hati+4hatj-2hatk) and (2hati+5hatj+13hatk) respectively. Locate the position of centre of mass.

The position vectors of two given points P and Q are 8hat(i)+3hat(j) " and " 2hat(i)-5hat(j) respectively, find the magnitude and direction of the vector vec(PQ)

(i) If the position vectors of the points A, B, C be 5hat(i)+3hat(j)+4hat(k), hat(i)+5hat(j)+hat(k) " and " -3hat(i)+7hat(j)-2hat(k) respectively, then show that the points B bisects the line-segment bar(AC) . (ii) The position vectors of the points P and Q are 5hat(i)-12hat(j)+5hat(k) " and " -4hat(i)+3hat(j)-hat(k) respectively. Find the position vectors of the trisection points of the line-segment bar(PQ) .

If 4 hat i+7 hat j+8 hat k ,2 hat i+3 hat j+4hat ja n d2 hat i+5 hat j+7 hat k are the position vectors of the vertices A ,Ba n dC , respectively, of triangle A B C , then the position vecrtor of the point where the bisector of angle A meets B C is a. 2/3(-6 hat i-8 hat j- hat k) b. 2/3(6 hat i+8 hat j+6 hat k) c. 1/3(6 hat i+13 hat j+18 hat k) d. 1/3(5 hat j+12 hat k)

The position vectors of Pa n dQ are 5 hat i+4 hat j+a hat k and - hat i+2 hat j-2 hat k , respectively. If the distance between them is 7, then find the value of adot