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There is some mercury in a U-tube. Water...

There is some mercury in a U-tube. Water is poured into one of its arms and kerosene into the other. When the heights of the water and the kerosene oil are 4cm and 5cm respectively, the level of mercury in both the arms becomes the same. Calculate the density of kerosene oil.

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Verified by Experts

The correct Answer is:
`0.8g*cm^(-3)`
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A U-tube is partially filled with mercury. Kerosene oil is poured into one of its limbs and glycerine into the other. It is observed that, when the height of the kerosene oil becomes 20 cm and that of glycerine becomes 12.68 cm, the levels of the mercury column in the two limbs are at the same horizontal level. If the density of kerosene oil is 0.8g*cm^(-3) , then find that of glycerine.

A U-tube is partly filled with water. A liquid, immiscible in water, is poured into one arm until the level of the liquid comes to a height h above the water level in the other arm. The water in the second arm is at a height d above its previous level in this arm. Calculate the density of the liquid.

A U-tube of uniform cross-section contains some water. When 4cm^(3) of water is poured into it, the water level rises by 1 cm in each arm of the tube. Now if 10cm^(3) of oil is poured through one of the limbs, the water level rises further by 2.2 cm in the other limb. Calculate the density of the oil.

Mercury is poured into a U-tube of uniform bore such that the level of mercury remains 20 cm below the open ends in both arms. Now, one arm is filled completely with water and the other arm with kerosene. Calculate the lengths of the water column and the kerosene column. The specific gravities of kerosene and mercury are 0.8 and 13.6 resspectively.

A U-tube of uniform cross-section contains some mercury. If water is poured into one of the limbs up to a height of 13.4cm, then find the rise in the mercury level in the other limb. The density of mercury = 13.4g*cm^(-3) .

A U-tube of uniform bore containing paraffin oil in one limb and water in the other is placed vertically on a table. The top and the bottom of the paraffin oil column from the table are respectively at heights of 18.4 cm and 6.4 cm. The top of the water column is 16.6 cm above the table. Calculate the specific gravity of paraffin oil.

An air bubble of diameter 1 mm is formed at the bottom of a lake and when it rises to the surface of the water, its diameter becomes 2 mm. If the atmospheric pressure is 760 cm of mercury, then find the depth of the lake. (Density of mercury = 13.6g*cm^(-3) )

CHHAYA PUBLICATION-HYDROSTATICS-PROBLEM SET - II
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