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Water is flowing through a horizontal tu...

Water is flowing through a horizontal tube of unequal cross section . At a point where the velocity of water is `0.4 m. s^-1`, the pressure is 0.1 m Hg. What is the pressure at a point where the velocity of water is 0.8 m.`s^-1` ? The density of mercury`=13.6xx10^3kg. m^-3`.

Text Solution

Verified by Experts

According to Bernoulli.s theorem,
`1/2v_(1)^(2)+(p_1)/(rho)=1/2v_2^2+(p_2)/(rho)("since the tube is horizontal")`
or, `p_2=p_1+1/2rho(v_1^2-v_2^2)=0.1xx(13.6xx10^3)xx9.8+1/2xx10^3xx{(0.4)^2-(0.8)^2}`
`=13088 Pa=(13088)/((13.6xx10^3)xx9.8)` m Hg
`=0.0982` m Hg.
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