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The radius of a soap-bubble is increased...

The radius of a soap-bubble is increased from 1 cm to 3 cm. What amount of work is done for this ? The surface tension of soap-water is 26 dyn. `cm^-1`.

Text Solution

Verified by Experts

Work done = increase in area `xx` surface tension
`=4pi{(3)^2-(1)^2}xx26xx2`
`[because "the soap-bubble has two surfaces"]`
`=522.6 erg= 5.2276xx10^-4.` J.
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