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What will be the work done to form a soa...

What will be the work done to form a soap-bubble of radius 5 cm? The surface tension of soap-water = 70 dyn. `cm^-1`

Text Solution

Verified by Experts

Work done `=2xx4pir^2xxT=8pir^2T`
[r = radius of the soap-bubble and
T = surface tension of soap-water]
`=8xx(22)/(7)xx(5)^2xx70=44000` erg
`=0.0044 J.`
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