Home
Class 11
PHYSICS
Find the excess pressure inside a rain w...

Find the excess pressure inside a rain water drop of diameter 0.02 cm. The surface tension of water = `0.072 N. m^-1`.

Text Solution

Verified by Experts

Water drop has only one curved surface.
So, excess pressure of a water drop, `p=(2T)/(r )`
where, T = surface tension of water
r = radius of a water drop = `(0.02)/(2)=0.01 cm`
`=0.01xx10^-2 m`
`therefore p = (2xx0.072)/(0.01xx10^-2)=1440N. m^-2`.
Promotional Banner

Topper's Solved these Questions

  • VISCOSITY AND SURFACE TENSION

    CHHAYA PUBLICATION|Exercise EXERCISE (HIGHER ORDER THINKING SKILL (HOTS) QUESTIONS|26 Videos

  • VISCOSITY AND SURFACE TENSION

    CHHAYA PUBLICATION|Exercise MCQs|22 Videos

  • VECTOR

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|19 Videos

  • WBCHSE QUESTION PAPER -2019

    CHHAYA PUBLICATION|Exercise SECTION - II ( GROUP -D)|10 Videos

Similar Questions

Explore conceptually related problems

What is the excess pressure inside a spherical soap bubble of radius 5 cm if the surface tension of the soap film is 3.5xx10^(-2)Nm^(-1) ?

Find the pressure inside on air bubble of radius 0.1 mm just inside the surface of water. Surface tension of water = 72 dyn. cm^-1 .

1000 droplets of water having 2 mm diameter each coalesce to form a single drop. Given the surface tension of water is 0.072 N. m^-1 . The energy loss in the process is

Determine the surface energy of a liquid film formed on a ring of area 0.15 m^2 . The surface tension of the liquid =5N. m^-1 .

What will be the work done to form a soap-bubble of radius 5 cm? The surface tension of soap-water = 70 dyn. cm^-1