Home
Class 11
PHYSICS
Surface tension of soap solution = 27 dy...

Surface tension of soap solution `= 27 dyn. Cm^-1`. Calculate the excess pressure (in N. `m^-2`) inside a soap bubble of radius 3 cm.

Text Solution

Verified by Experts

The excess pressure inside a soap bubble,
`p=(4T)/(r )=(4xx27)/(3)= 36 dyn. cm^-2 = 3.6 N. m^-2`.
Promotional Banner

Topper's Solved these Questions

  • VISCOSITY AND SURFACE TENSION

    CHHAYA PUBLICATION|Exercise EXERCISE (HIGHER ORDER THINKING SKILL (HOTS) QUESTIONS|26 Videos

  • VISCOSITY AND SURFACE TENSION

    CHHAYA PUBLICATION|Exercise MCQs|22 Videos

  • VECTOR

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|19 Videos

  • WBCHSE QUESTION PAPER -2019

    CHHAYA PUBLICATION|Exercise SECTION - II ( GROUP -D)|10 Videos

Similar Questions

Explore conceptually related problems

If the surface tension of soap water is 27 dyne/cm then what will be the excess pressure inside the bubble of 3 cm radius.

If the surface tension of water is 7.3xx10^-2 N. m^-1 , then what is the pressure inside a spherical drop of water of radius 10^-3 m?

Let n number of little droplets of water of surface tension S dyn. Cm^-1 , all of the same radius r cm, combine to form a single drop of radius R cm. J is joule's mechanical equivalent of heat. While using CGS system of units answer the following questions. i. The energy released is

The excess of pressure inside a soap bubble is twice the excess pressure inside a second soap bubble. The volume of the first bubble in n times the volume of the second. What is the value of n?