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A substance is heated from 30^(@)C " to ...

A substance is heated from `30^(@)C " to " 75^(@)C`. What is the change in its temperature on the Fahrenheit scale and on the Kelvin scale?

Text Solution

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Let a temperature be C on the Celsius scale, F on the Fahrenheit scale and T on the Kelvin scale. We can write,
`F=9/5C+32 " "`…(1)
and T=C+23 `" "`...(2)
Differentiate equation (1) we get,
`DeltaF=9/5DeltaC`
Here, `DeltaC=75-30=45 " " therefore DeltaF=9/5 times 45=81.`
Similarly, differentiating equation (2) we get,
`DeltaT=DeltaC=45`.
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