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An iron saucepan contains 100 g of water...

An iron saucepan contains 100 g of water at `25^(@)C`. When 50 g of water at `60^(@)C` is mixed with it, the final temperature of the mixture becomes `35^(@)C`. If no heat is lost due to radiation or other means, then what is the water equivalent of the saucepan? If hte mass of this saucepan is 238 g, then what is the specific heat of iron?

Text Solution

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`"25g, 0.105 cal . g"^(-1).^(@)C^(-1)`
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