At equilibrium the volume pressure and temperature of a gas are V,p and T respectively. IF the gas is divided into two parts by a equation, what will be the value of these quantities in each part?

Explanation

The rms speed of gas molecules does not depend on the volume of the container. SO speed does not change when the volume of the gas is halved by using a partition. As a result, temperature remains the same. As the density of gas does not undergo any change and as `p=1/3pc^2` pressure will also remain the same. Thus only the volume becomes half,but pressure and temperature remain the same. So, the values of volume,pressure and temperature will `v/2`,p and T respectively.