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Find out the temperature at which the av...

Find out the temperature at which the average translational kinetic energy of a gas molecule will be equal to the energy gained by an electron on acceleration across a potential difference of 5V, Boltzmann constant, `k=1.38 times 2.^-23 J.K^-1 1 ev=1.6 times 10^-19 J`.

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The correct Answer is:
`38.65 times 10^3 K`
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CHHAYA PUBLICATION-KINETIC THEORY OF GASES-EXERCISE ( Hot Numerical problems)
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