A particle of mass m is executing simple harmonic motion with an amplitude A. If the mass of the particle is reduced by 50%, then what will be its (i) new frequency, (ii) new total energy?

A particle of mass m executes SHM with an amplitude A. If its mass is changed to 1/4 m, then what will be its (i) new frequency and (ii) total energy?

If a particle of mass m is maintaining an S.H.M. with amplitude A. If the mass is changed to m/4 then:- what will be the new frequency?

A particle executives simple harmonic motion of amplitude A. The distance from the mean position where its kinetic energy is equal to its potential energy is

A particle of mass 0.01 kg is executing simple harmonic motion along a straight line. Its time period is 2 s and amplitude is 0.1 m. Determine its kinetic energy (i) at a distance 0.02 m and (ii) at a distance 0.05 m from the position of equilibrium.

A particle of mass m has momentum p. What is its kinetic energy ?

For a particle executing simple harmonic motion, find the distance from the mean position at which its potential and kinetic energies are equal.

A particle performs simple harmonic motion with amplitude A. Its speed is trebled at the instant that it is at a distance (2A)/3 from equilibrium position. The new amplitude of the motion is

Total energy of a particle executing simple harmonic motion is 400 erg and the maximum force acting on the particle is 100 dyn. If the time period is 2 s and the initial phase is 30^(@) , then write down the equation of motion. What is the mass of the particle?