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A particle of mass 0.01 kg is executing ...

A particle of mass 0.01 kg is executing simple harmonic motion along a straight line. Its time period is 2 s and amplitude is 0.1 m. Determine its kinetic energy (i) at a distance 0.02 m and (ii) at a distance 0.05 m from the position of equilibrium.

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The correct Answer is:
`(i)4.8xx10^(-4)J;" "(ii)3.75xx10^(-4)J`
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