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The number of possible natural oscillat...

The number of possible natural oscillations of air col-umn in a pipe closed at one end of length 85 cm when frequencies lie below 1250 Hz are (velocity of sound ` = 350 m*s^(-1)`

A

4

B

5

C

7

D

6

Text Solution

Verified by Experts

The correct Answer is:
D
Velocity of sound `(V) = 340 m*s^(-1) = 34000 cm *s^(-1)`
Length of closed pipe (l) = 85 cm
So, fundamental frequency .
`n_(0) = (V)/(4l) = (34000)/(4 xx 85) = 100 `Hz
Thus, present natural frequencies are odd multiple of fundamentla frequency, i.e., 100, 300, 500, 700, 900, 110
So, number of natural oscillations = 6
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