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DIPTI PUBLICATION ( AP EAMET)-DEFINITE INTEGRATION-EXERCISE 1A
- int(0)^(2)(3x^(2)+4x+3)dx=
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- int(0)^(pi//4)sec^(2)xdx=
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- int(0)^(pi//2)sqrt(1+sin2xdx)
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- The value of I=int(0)^(pi//2)((sinx+cosx)^(2))/(sqrt(1+sin2x))dx is
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- int(0)^(1)(1)/(1+x)dx=
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- int(0)^(1)(x)/(1+x^(2))dx=
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- int(0)^(pi//2)(cosx)/(1+sinx)dx=
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- int(1//2)^(1)(1)/(sqrt(1-x^(2)))dx=
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- int(sqrt2//3)^(sqrt(3)/3)(dx)/(sqrt(4-9x^(2)))=
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- int(-1)^(1)(1)/(1+x^(2))dx=
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- int(-1)^(1)(1)/((1+x^(2))^(2))dx=
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- int(0)^(1)sqrt(1-x^(2))dx
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- Evaluate underset(0)overset(a)int sqrt(a^(2)-x^(2)) dx
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- int(pi//6)^(5pi//6)sqrt(4-4sin^(2)t)" "dt=
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- The value of the integral int(0)^(3)(dx)/(sqrt(x+1)+sqrt(5x+1)) is
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- int(0)^(1)(4x^(3))/(sqrt(1-x^(8)))dx=
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- int(0)^(1)(x^(3))/(1+x^(8))dx=
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- int(0)^(pi//4)(tan^(4)x+tan^(3)x)dx=
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- int(0)^(pi//4)(e^(tanx))/(cos^(2)x)dx=
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- int(1//sqrt3)^(1)(Tan^(-1)x)^(3)/(1+x^(2))dx=
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