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If f(x)={{:(x^(2)" for "0lexle1),(sqrtx"...

If `f(x)={{:(x^(2)" for "0lexle1),(sqrtx" for "1lexle2):}" then "int_(0)^(2)f(x)dx=`

A

`(1//3)(4sqrt2+1)`

B

`(1//3)(4sqrt2-1)`

C

`(1//3)(2sqrt2-1)`

D

`(1//2)(3sqrt2-1)`

Text Solution

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