int(0)^(pi)(1)/(1+sinx)dx=...

`int_(0)^(pi)(1)/(1+sinx)dx=`

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int(pi//2)^(pi//2)e^(sin^(2)x).sin^(2n+1)xdx=
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int(0)^(pi)(1)/(1+sinx)dx=
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int(pi//4)^(3pi//4)(1)/(1+cosx)dx
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int(0)^(3)xsqrt(1+x)dx=
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int(0)^(1)(dx)/(x+sqrt(x))=
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int(0)^(1)(x)/(1+sqrtx)dx=
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int(pi^(2)//16)^(pi^(2//4))(sinsqrtx)/(sqrtx)dx=
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int(0)^(1)(x)/((1-x)^(5//4))dx=
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int(1//3)^(1)(x-x^(3))^(1//3)/(x^(4))dx=
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int(0)^(pi)sin^(3)xcos^(4)xdx=
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int(0)^(pi//2)sin^(6)xcos^(5)xdx=
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int(0)^(pi)-(sin^(3)x)/(1+cos^(3)x)dx
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int(0)^(pi//4)(sin^(9)x)/(cos^(11)x)dx=
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int(r//6)^(pi//4)(dx)/(sin2x)=
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int(0)^(pi)(tanx)/(secx+cosx)dx=
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int(0)^(oo) (x)/((1+x)(1+x^(2)))dx=
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If int(0)^(k)(cosx)/(1+sin^(2)x)dx=(pi)/(4) then k=
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int(0)^(oo)(1)/(1+x)^(4)dx=
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int(-1)^(1)xe^(x)dx=
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