int(0)^(pi^(2)//4)cossqrtxdx=...

`int_(0)^(pi^(2)//4)cossqrtxdx=`

`pi-2`

`pi+2`

`(pi//2)-1`

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int(0)^(1)Tan^(-1)[(2x-1)/(1+x-x^(2))]dx=
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int(0)^(pi^(2)//4)sinsqrtxdx=
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int(0)^(pi^(2)//4)cossqrtxdx=
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int(0)^(pi//2)(cosx-sinx)e^(x)dx=
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int(0)^(1)(xe^(x))/((x+1)^(2))dx=
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int(0)^(pi)e^(x)sinxdx=
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If int(0)^(b)(dx)/(1+x^(2))=int(b)^(oo)(dx)/(1+x(2)), then b=
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int(0)^(pi//4)[sqrt(tan x) + sqrt(cot x)] = dx
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int(0)^(pi//4)(sinx + cos x)/(7+9 sin 2x) dx =
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If I(1)=int(e)^(e^(2))(dx)/(logx)andI(2)=int(1)^(2)(e^(x))/(x)dx, then
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If I=int(0)^(1)sqrt(1+x^(3))dx then
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If I=int(0)^(1)(dx)/(sqrt(1+x^(4))), then
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Evaluate the integral underset(0)overset(pi//2)int (dx)/(4+5cosx )
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int(0)^(pi//2)(1)/(2+3sinx)dx=
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int(0)^(pi)(1)/(3+2sinx+cosx)dx=
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int(0)^(pi//2)(1)/(1+4sin^(2)x)dx=
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int(0)^(pi//2)(1)/(4cos^(2)x+9sin^(2)x)dx=
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int(0)^(pi)(xdx)/(a^(2)cos^(2)x+b^(2)sin^(2)x)=
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int(0)^(pi//4)(sinx+cosx)/(3+sin2x)dx=
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