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DIPTI PUBLICATION ( AP EAMET)-DEFINITE INTEGRATION-EXERCISE 1B
- int(-pi//2)^(pi//2)cosx.sinhxdx=
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- int(-pi//2)^(pi//2) sinx sechxdx=
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- int(-1)^(1)(coshx)/(1+e^(x))dx=
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- int(-1)^(1)(coshx)/(1+e^(2x))dx=
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- int(-pi//2)^(pi//2)(cosx)/(1-e^(x))dx=
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- Evaluate the definite integrals . underset(-pi//2)overset(pi//2)int ...
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- The value of int(-pi)^(pi)(cos^(2)x)/(1+a^(x))dx,agt0 is
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- agt0,int(-pi)^(pi)(sin^(2)x)/(1+a^(x))dx=
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- int(-1)^(1)(ax^(3)+bx)dx=0 for
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- If int(0)^(x)f(t)dt=x+int(x)^(1)tf(t)dt, then the value of f(1) is
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- If f(y)=e^(y),g(y)=y:ygt0andF(t)=int(0)^(t)f(t-y)g(y)dy, then
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- The solution for x of the equation int(sqrt2)^(x)(dt)//t(sqrt(t^(2)-1)...
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- int(log2)^(t)(dx)/(sqrt(e^(x)-1))=(pi)/(6), then t=
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- int(0)^(pi//2)(sqrt(sinx))/(sqrt(sinx)+sqrt(cosx))dx=
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- int(0)^(pi//2)(cos^(3//2)x)/(cos^(3//2)x+sin^(3//2)x)dx=
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- int(pi//6)^(pi//3)(sin^(3)x)/(sin^(3)x+cos^(3)x)dx=
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- int(0)^(pi//2)(secx)/(secx+cosecx)dx=
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- int(0)^(pi//2)(cotx)/(tanx+cotx)dx=
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- int(0)^(pi//2)(sqrt(cotx))/(sqrt(tanx)+sqrt(cotx))dx=
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- int(0)^(pi//2)(1)/(1+sqrt(cotx))dx=
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