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Ig |bar(a)| = 11 ,|bar(b)| = 23,|bar(a)-...

Ig `|bar(a)| = 11 ,|bar(b)| = 23,|bar(a)-bar(b)| = 30` then find the angle between the vectors `bar(a),bar(b)` and also find `|bar(a)+bar(b)|`.

Text Solution

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The correct Answer is:
`|bara+barb|=20`
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Knowledge Check

  • The vector abar(i)+b""bar(j)+cbar(k) is a bisector of the angle between the vectors bar(i)+bar(j) and bar(j)+bar(k) if

    A
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    C
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    D
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