In the electrochemical cell: `Znabs(ZnSO_(4)(0.01M))abs(CuSO_(4)(1.0M))Cu`, the emf of this Daniel cell is `E_(1)`. When the concentration of `ZNSO_(4)` is changed to 1.0 M and that `CuSO_(4)` changed to 0.01M, the emf changes to `E_(2)`. From the followings, which one is the relationship between `E_(1) " and "E_(2)`?

Options

A. `E_(1) lt E_(2)`
B. `E_(1) gt E_(2)`
C. `E_(2)=0 ge E_(1)`
D. `E_(1)=E_(2)`

Answer

B