State Faraday's Laws of electrolysis.

Explanation

First Law : The mass of the substance (m) liberated at an electrode during electrolysis is directly proportional to the quantity of charge (Q) passed through the cell.
i.e `m" "alpha" "Q`
We know that the charge is related to the current by the equation
`" "therefore m" "alpha" "It`
`" "`(or)
`" "` m = Z It
Where is Z is known as the electro chemical equivalent of the substance produced of the electrode.

Second Law : When the same quantity of charge is passed through the solutions of different electrolytes, the amount of substances liberated at the respective electrodes are directly proportional to their electrochemical equivalents.
When Q coulomb charge is passed through the electrolytic cells the masses of silver, zinc and copper deposited at the respective electrodes be `m_(Ag), m_(Zn) " and " m_(Cu)`, respectively.
According to Faraday.s second Law,
`m_(Ag)" "alpha" "Z_(Ag), m_(Zn) " and " m_(Cu)" "alpha" "Z_(Cu)`,
`" "`(or)
`m_(Ag)/Z_(Ag)=m_(Zn)/Z_(Zn)=m_(Cu)/Z_(Cu)`